2017-03-03 09:55:01, entered by englund for cdlistaff
&P125395 = OrSP 47-49, 507
#atf: lang sux
@tablet
@obverse
1.a. 2(u)
1.b. 5(u)
1.c. 5(iku) GAN2 bar
# calculation: (20 × 50) ÷ 2 = 500 sar = 5i
2.a. 2(u)
2.b. 4(u)
2.c. 4(iku) bar
# calculation: (20 × 40) ÷ 2 = 400 sar = 4i
3. 1(u)
4.a. 1(u)
4.b. 4(u)
4.c. 2(iku) ki
# calculation: (10 × 40) ÷ 2 = 200 sar = 2i
5.a. 1(u)
5.b. 5(u) 5(disz)
5.c. 2(iku) 1/2(iku) 1/4(iku) ki
# calculation: (10 × 55) ÷ 2 = 275 sar = 2.75i
6. 1(iku) 1/4(iku) bar
# meaning ? (the unfinished triangle to the right would be (20 × 15) ÷ 2 = 1.5i)
7. 4(u)
8. 2(u)
9.a.1. 1(u) 5(disz)
9.a.2. 2(u)
9.b. 3(u)
9.c. 5(iku) 1/4(iku) <bar>
# calculation: (15 + 20)/2 × 30 = 525 sar = 5.25i
10. 2(gesz2) 3(u)
11.a. 1(gesz2) 1(u)
11.b. 5(u)
11.c. 1(bur3) 2(esze3) 5(iku)
# calculation: 70 × 50 = 3500 = 1b 2e 5i
12. 2(esze3) 4(iku) 1/2(iku) 1/4(iku)
# calculation: (40 + 30)/2 x (45 + 50)/2 = 1662.5 ≈ 2e 4.75i
13. 2(bur3) 2(esze3) 2(iku)
# calculation: (((40 + 10 + 40 + 10) + (150 - 50)) ÷ 2) = 100 × (((-10 + 40 + 20) + (70 - 20)) ÷ 2) =) 50 = 5000 = 2b 2e 2i
@reverse
@column 1
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
# calculation: 1.c. + 2.c. + 6 + 9.c = 2e 3.5i
2. 5(bur3) 1(esze3) 1(iku) GAN2
# calculation: 11.c. + 12 + 13 - (4.c + 5.c.) = 5b 1e 1i
3. 4(iku) 1/2(iku) 1/4(iku) ki zi
# calculation: 4.c + 5.c. = 4.75i
4. szunigin 6(bur3) 4(iku) 1/2(iku) GAN2
# calculation: rev i 1 + 2 = 6b 4.5i
5. a-sza3 na-ga-ab-tum
6. {d}szul-pa-e3
$ blank space
@column 2
$ blank space

2014-10-31 14:49:27, entered by englund for englund
&P125395 = OrSP 47-49, 507
#atf: lang sux
@tablet
@obverse
1.a. 2(u)
1.b. 5(u)
1.c. 5(iku) GAN2 bar
# calculation: (20 × 50) ÷ 2 = 500 sar = 5i
2.a. 2(u)
2.b. 4(u)
2.c. 4(iku) bar
# calculation: (20 × 40) ÷ 2 = 400 sar = 4i
3. 1(u)
4.a. 1(u)
4.b. 4(u)
4.c. 2(iku) ki
# calculation: (10 × 40) ÷ 2 = 200 sar = 2i
5.a. 1(u)
5.b. 5(u) 5(disz)
5.c. 2(iku) 1/2(iku) 1/4(iku) ki
# calculation: (10 × 55) ÷ 2 = 275 sar = 2.75i
6. 1(iku) 1/4(iku) bar
# meaning ? (the unfinished triangle to the right would be (20 × 15) ÷ 2 = 1.5i)
7. 4(u)
8. 2(u)
9.a.1. 1(u) 5(disz)
9.a.2. 2(u)
9.b. 3(u)
9.c. 5(iku) 1/4(iku) <bar>
# calculation: (15 + 20)/2 × 30 = 525 sar = 5.25i
10. 2(gesz2) 3(u)
11.a. 1(gesz2) 1(u)
11.b. 5(u)
11.c. 1(bur3) 2(esze3) 5(iku)
# calculation: 70 × 50 = 3500 = 1b 2e 5i
12. 2(esze3) 4(iku) 1/2(iku) 1/4(iku)
# calculation: (40 + 30)/2 x (45 + 50)/2 = 1662.5 ≈ 2e 4.75i
13. 2(bur3) 2(esze3) 2(iku)
# calculation: (((40 + 10 + 40 + 10) + (150 - 50)) ÷ 2) = 100 × (((-10 + 40 + 20) + (70 - 20)) ÷ 2) =) 50 = 5000 = 2b 2e 2i
@reverse
@column 1
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
# calculation: 1.c. + 2.c. + 6 + 9.c = 2e 3.5i
2. 5(bur3) 1(esze3) 1(iku) GAN2
# calculation: 11.c. + 12 + 13 - (4.c + 5.c.) = 5b 1e 1i
3. 4(iku) 1/2(iku) 1/4(iku) ki zi
# calculation: 4.c + 5.c. = 4.75i
4. |SZU+LAGAB| 6(bur3) 4(iku) 1/2(iku) GAN2
# calculation: rev i 1 + 2 = 6b 4.5i
5. a-sza3 na-ga-ab-tum
6. {d}szul-pa-e3
$ blank space
@column 2
$ blank space

2014-10-30 18:20:52, entered by englund for friberg
&P125395 = OrSP 47-49, 507
#atf: lang sux
@tablet
@obverse
1.a. 2(u)
1.b. 5(u)
1.c. 5(iku) GAN2 bar
# calculation: (20 × 50) ÷ 2 = 500 sar = 5i
2.a. 2(u)
2.b. 4(u)
2.c. 4(iku) bar
# calculation: (20 × 40) ÷ 2 = 400 sar = 4i
3. 1(u)
4.a. 1(u)
4.b. 4(u)
4.c. 2(iku) ki
# calculation: (10 × 40) ÷ 2 = 200 sar = 2i
5.a. 1(u)
5.b. 5(u) 5(disz)
5.c. 2(iku) 1/2(iku) 1/4(iku) ki
# calculation: (10 × 55) ÷ 2 = 275 sar = 2.75i
6. 1(iku) 1/4(iku)? bar
# meaning ? (the unfinished triangle to the right would be 15 × 20 ÷ 2 = 1.5i)
7. 4(u)
8. 2(u)
9.a.1. 1(u) 5(disz)
9.a.2. 2(u)
9.b. 3(u)
9.c. 5(iku) 1/4(iku) <bar>
# calculation: (15 + 20)/2 × 30 = 525 sar = 5.25i
10. 2(gesz2) 3(u)
11.a. 1(gesz2) 1(u)
11.b. 5(u)
11.c. 1(bur3) 2(esze3) 5(iku)
# calculation: 70 × 50 = 3500 = 1b 2e 5i
12. 2(esze3) 4(iku) 1/2(iku) 1/4(iku)
# calculation: 40 × (50) = 2000 - (325) = 1675 = 2e 4.75i (?)
# Friberg (s. _ld): (40 + 27?)/2 × 50 = 1675 = 2e 4.75i (?)
13. 2(bur3) 2(esze3) 2(iku)
# calculation: (((40 + 10 + 40 + 10) + (150 - 50)) ÷ 2) = 100 × (((-10 + 40 + 20) + (70 - 20)) ÷ 2) =) 50 = 5000 = 2b 2e 2i (J. Friberg)
@reverse
@column 1
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
# calculation: 5i + 4i + 1.25i + 5.25i = 2e 3.5i
2. 5(bur3) 1(esze3) 1(iku) GAN2
# calculation: 1b 2e 5i + ((50 + 60)/2 × 100 = 5500 =) 3b 1i + (40 × 50 = 2000 =) 1b 2i = 6b 2i - (2e 1i ?; text 5b 1e 1i)
3. 4(iku) 1/2(iku) 1/4(iku) ki zi
# calculation: 2i + 2 3/4i = 4 3/4i
4. |SZU+LAGAB| 6(bur3) 4(iku) 1/2(iku) GAN2
# calculation: (2e 3 1/2i) + (5b 1e 1i) = 6b 4 1/2i
5. a-sza3 na-ga-ab-tum
6. {d}szul-pa-e3
$ blank space
@column 2
$ blank space

2014-10-30 18:00:57, entered by englund for englund
&P125395 = OrSP 47-49, 507
#atf: lang sux
@tablet
@obverse
1.a. 2(u)
1.b. 5(u)
1.c. 5(iku) GAN2 bar
# calculation: (20 × 50) ÷ 2 = 500 sar = 5i
2.a. 2(u)
2.b. 4(u)
2.c. 4(iku) bar
# calculation: (20 × 40) ÷ 2 = 400 sar = 4i
3. 1(u)
4.a. 1(u)
4.b. 4(u)
4.c. 2(iku) ki
# calculation: (10 × 40) ÷ 2 = 200 sar = 2i
5.a. 1(u)
5.b. 5(u) 5(disz)
5.c. 2(iku) 1/2(iku) 1/4(iku) ki
# calculation: (10 × 55) ÷ 2 = 275 sar = 2.75i
6. 1(iku) 1/4(iku)? bar
# meaning ? (the unfinished triangle to the right would be 15 × 20 ÷ 2 = 1.5i)
7. 4(u)
8. 2(u)
9.a.1. 1(u) 5(disz)
9.a.2. 2(u)
9.b. 3(u)
9.c. 5(iku) 1/4(iku) <bar>
# calculation: (15 + 20)/2 × 30 = 525 sar = 5.25i
10. 2(gesz2) 3(u)
11.a. 1(gesz2) 1(u)
11.b. 5(u)
11.c. 1(bur3) 2(esze3) 5(iku)
# calculation: 70 × 50 = 3500 = 1b 2e 5i
12. 2(esze3) 4(iku) 1/2(iku) 1/4(iku)
# calculation: 40 × (50) = 2000 - (325) = 1675 = 2e 4.75i (?)
# Friberg (s. _ld): (40 + 27?)/2 × 50 = 1675 = 2e 4.75i (?)
13. 2(bur3) 2(esze3) 2(iku)
# calculation: (1b 2e 5i) + (2e 4 3/4i) = 2b 2e 3 3/4i (?; text 2b 2e 2i)
# Friberg (s. _ld): 100 × 50 = 5000 = 2b 2e 2i
@reverse
@column 1
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
# calculation: 5i + 4i + 1.25i + 5.25i = 2e 3.5i
2. 5(bur3) 1(esze3) 1(iku) GAN2
# calculation: 1b 2e 5i + ((50 + 60)/2 × 100 = 5500 =) 3b 1i + (40 × 50 = 2000 =) 1b 2i = 6b 2i - (2e 1i ?; text 5b 1e 1i)
3. 4(iku) 1/2(iku) 1/4(iku) ki zi
# calculation: 2i + 2 3/4i = 4 3/4i
4. |SZU+LAGAB| 6(bur3) 4(iku) 1/2(iku) GAN2
# calculation: (2e 3 1/2i) + (5b 1e 1i) = 6b 4 1/2i
5. a-sza3 na-ga-ab-tum
6. {d}szul-pa-e3
$ blank space
@column 2
$ blank space

2014-10-18 09:10:31, entered by englund for englund
&P125395 = OrSP 47-49, 507
#atf: lang sux
@tablet
@obverse
1.a. 2(u)
1.b. 5(u)
1.c. 5(iku) GAN2 bar
# calculation: (20 × 50) ÷ 2 = 500 sar = 5i
2.a. 2(u)
2.b. 4(u)
2.c. 4(iku) bar
# calculation: (20 × 40) ÷ 2 = 400 sar = 4i
3. 1(u)
4.a. 1(u)
4.b. 4(u)
4.c. 2(iku) ki
# calculation: (10 × 40) ÷ 2 = 200 sar = 2i
5.a. 1(u)
5.b. 5(u) 5(disz)
5.c. 2(iku) 1/2(iku) 1/4(iku) ki
# calculation: (10 × 55) ÷ 2 = 275 sar = 2.75i
6. 1(iku) 1/4(iku)? bar
# meaning ? (the unfinished triangle to the right would be 15 × 20 ÷ 2 = 1.5i)
7. 4(u)
8. 2(u)
9.a.1. 1(u) 5(disz)
9.a.2. 2(u)
9.b. 3(u)
9.c. 5(iku) 1/4(iku) <bar>
# calculation: (15 + 20)/2 × 30 = 525 sar = 5.25i
10. 2(gesz2) 3(u)
11.a. 1(gesz2) 1(u)
11.b. 5(u)
11.c. 1(bur3) 2(esze3) 5(iku)
# calculation: 70 × 50 = 3500 = 1b 2e 5i
12. 2(esze3) 4(iku) 1/2(iku) 1/4(iku)
# calculation: 40 × (50) = 2000 - (325) = 1675 = 2e 4.75i (?)
13. 2(bur3) 2(esze3) 2(iku)
# calculation: (1b 2e 5i) + (2e 4 3/4i) = 2b 2e 3 3/4i (?; text 2b 2e 2i)
@reverse
@column 1
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
# calculation: 5i + 4i + 1.25i + 5.25i = 2e 3.5i
2. 5(bur3) 1(esze3) 1(iku) GAN2
# calculation: 1b 2e 5i + ((50 + 60)/2 × 100 = 5500 =) 3b 1i + (40 × 50 = 2000 =) 1b 2i = 6b 2i - (2e 1i ?; text 5b 1e 1i)
3. 4(iku) 1/2(iku) 1/4(iku) ki zi
# calculation: 2i + 2 3/4i = 4 3/4i
4. |SZU+LAGAB| 6(bur3) 4(iku) 1/2(iku) GAN2
# calculation: (2e 3 1/2i) + (5b 1e 1i) = 6b 4 1/2i
5. a-sza3 na-ga-ab-tum
6. {d}szul-pa-e3
$ blank space
@column 2
$ blank space

2014-10-17 10:52:29, entered by englund for englund
&P125395 = OrSP 47-49, 507
#atf: lang sux
@tablet
@obverse
1.a. 2(u)
1.b. 5(u)
1.c. 5(iku) GAN2 bar
# calculation: (20 × 50) ÷ 2 = 500 sar = 5i
2.a. 2(u)
2.b. 4(u)
2.c. 4(iku) bar
# calculation: (20 × 40) ÷ 2 = 400 sar = 4i
3.a. 1(u)
3.b. 4(u)
3.c. 2(iku) ki
# calculation: (10 × 40) ÷ 2 = 200 sar = 2i
4.a. 1(u)
4.b. 5(u) 5(disz)
4.c. 2(iku) 1/2(iku) 1/4(iku) ki
# calculation: (10 × 55) ÷ 2 = 275 sar = 2.75i
5. 1(iku) 1/4(iku)? bar
# meaning ? (the unfinished triangle to the right would be 15 × 20 ÷ 2 = 1.5i)
6. 4(u)
7. 2(u)
8.a.1. 1(u) 5(disz)
8.a.2. 2(u)
8.b. 3(u)
8.c. 5(iku) 1/4(iku) <bar>
# calculation: (15 + 20)/2 × 30 = 525 sar = 5.25i
9. 2(gesz2) 3(u)
10.a. 1(gesz2) 1(u)
10.b. 5(u)
10.c. 1(bur3) 2(esze3) 5(iku)
# calculation: 70 × 50 = 3500 = 1b 2e 5i
11. 2(esze3) 4(iku) 1/2(iku) 1/4(iku)
# calculation: 40 × (50) = 2000 - (325) = 1675 = 2e 4.75i (?)
12. 2(bur3) 2(esze3) 2(iku)
# calculation: (1b 2e 5i) + (2e 4 3/4i) = 2b 2e 3 3/4i (?; text 2b 2e 2i)
@reverse
@column 1
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
# calculation: 5i + 4i + 1.25i + 5.25i = 2e 3.5i
2. 5(bur3) 1(esze3) 1(iku) GAN2
# calculation: 1b 2e 5i + ((50 + 60)/2 × 100 = 5500 =) 3b 1i + (40 × 50 = 2000 =) 1b 2i = 6b 2i - (2e 1i ?; text 5b 1e 1i)
3. 4(iku) 1/2(iku) 1/4(iku) ki zi
# calculation: 2i + 2 3/4i = 4 3/4i
4. |SZU+LAGAB| 6(bur3) 4(iku) 1/2(iku) GAN2
# calculation: (2e 3 1/2i) + (5b 1e 1i) = 6b 4 1/2i
5. a-sza3 na-ga-ab-tum
6. {d}szul-pa-e3
$ blank space
@column 2
$ blank space

2014-10-17 10:28:19, entered by englund for englund
&P125395 = OrSP 47-49, 507
#atf: lang sux
@tablet
@obverse
1.a. 2(u)
1.b. 5(u)
1.c. 5(iku) GAN2 bar
# calculation: (20 × 50) ÷ 2 = 500 sar = 5i
2.a. 2(u)
2.b. 4(u)
2.c. 4(iku) bar
# calculation: (20 × 40) ÷ 2 = 400 sar = 4i
3.a. 1(u)
3.b. 4(u)
3.c. 2(iku) ki
# calculation: (10 × 40) ÷ 2 = 200 sar = 2i
4.a. 1(u)
4.b. 5(u) 5(disz)
4.c. 2(iku) 1/2(iku) 1/4(iku) ki
# calculation: (10 × 55) ÷ 2 = 275 sar = 2 3/4i
5. 1(iku) 1/4(iku)? bar
# meaning ? (the unfinished triangle to the right would be 15 × 20 ÷ 2 = 1.5i)
6. 4(u)
7. 2(u)
8.a.1. 1(u) 5(disz)
8.a.2. 2(u)
8.b. 3(u)
8.c. 5(iku) 1/4(iku) ki
# calculation: (15 + 20)/2 × 30 = 525 sar = 5 1/4i
9. 2(gesz2) 3(u)
10.a. 1(gesz2) 1(u)
10.b. 5(u)
10.c. 1(bur3) 2(esze3) 5(iku)
# calculation: 70 × 50 = 3500 = 1b 2e 5i
11. 2(esze3) 4(iku) 1/2(iku) 1/4(iku)
# calculation: 40 × (50) = 2000 - (325) = 1675 = 2e 4 3/4i (?)
12. 2(bur3) 2(esze3) 2(iku)
# calculation: (1b 2e 5i) + (2e 4 3/4i) = 2b 2e 3 3/4i (?; text 2b 2e 2i)
@reverse
@column 1
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
# calculation: 5i + 4i + 1 1/2i + (5i) = 2e 3 1/2i
2. 5(bur3) 1(esze3) 1(iku) GAN2
# calculation: 1b 2e 5i + ((50 + 60)/2 × 100 = 5500 =) 3b 1i + (40 × 50 = 2000 =) 1b 2i = 6b 2i - (2e 1i ?; text 5b 1e 1i)
3. 4(iku) 1/2(iku) 1/4(iku) ki zi
# calculation: 2i + 2 3/4i = 4 3/4i
4. |SZU+LAGAB| 6(bur3) 4(iku) 1/2(iku) GAN2
# calculation: (2e 3 1/2i) + (5b 1e 1i) = 6b 4 1/2i
5. a-sza3 na-ga-ab-tum
6. {d}szul-pa-e3
$ blank space
@column 2
$ blank space

2011-07-22 13:54:24, entered by englund for englund
&P125395 = OrSP 47-49, 507
#atf: lang sux
@tablet
@obverse
$ (Field plan)
$ ((dimensions and measures)
@reverse
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
2. 5(bur3) 1(esze3) 1(iku) GAN2
3. 4(ban2) ki zi
# erasure
4. |SZU+LAGAB| 6(bur3) 4(iku) 1/2(iku) GAN2
5. a-sza3 na-ga-ab-tum
6. {d}szul-pa-e3

2011-05-02 14:28:43, entered by englund for englund
&P125395 = OrSP 47-49, 507
#atf: lang sux
@tablet
@obverse
$ (Field plan)
$ ((dimensions and measures)
@reverse
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
2. 5(bur3) 1(esze3) 1(iku) GAN2
3. 4(ban2) ki zi
# erasure
4. |SZU+LAGAB| 6(bur3) 4(iku) 1/2(iku) GAN2
5. a-sza3 na-ga-ab-tum
6. {d}szul-pa-e3

2006-10-12 12:24:33, entered by cdlistaff for cdlistaff
&P125395 = OrSP 47-49, 507
#version: 0.1
#atf: lang sux
@tablet
@obverse
$ (Field plan)
$ ((dimensions and measures)
@reverse
1. 2(esze3) 3(iku) 1/2(iku) GAN2 bar
#lem: n; n; n; iku[unit]; bar[outside]
2. 5(bur3) 1(esze3) 1(iku) GAN2
#lem: n; n; n; iku[unit]
3. 4(ban2) ki zi
#lem: n; ki[place]; zi[life]
# (#erasure#)* ki zi
4. |SZU+LAGAB| 6(bur3) 4(iku) 1/2(iku) GAN2
#lem: szunijin[total]; n; n; n; iku[unit]
5. a-sza3 na-ga-ab-tum
#lem: aszag[field]; FN
6. {d}szul-pa-e3
#lem: DN