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TCL 05, 5677
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Primary publicationTCL 05, 5677
Author(s)Genouillac, Henri de
Publication date1922
Secondary publication(s)
CollectionLouvre Museum, Paris, France
Museum no.AO 05677
Accession no.
ProvenienceUmma (mod. Tell Jokha)
Excavation no.
PeriodUr III (ca. 2100-2000 BC)
Dates referenced--.--.00.00
Object typetablet
Remarks
Materialclay
LanguageSumerian
GenreAdministrative
Sub-genrefield plan (drawing)
CDLI comments20081101 englund: graphic description of field plan calculations added rke.
Catalogue source20011220 ur3_catalogue
ATF sourceDahl, Jacob L.; Englund, Robert K.
Translationno translation
UCLA Library ARK21198/zz001rg6td
Composite no.
Seal no.
CDLI no.P131748

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Tablet


obverse
1. 1(u)
2.a. 3(u)
2.b. 1(u) 6(disz)
2.c. 1(esze3) 1/4(iku) bar
calculation: 30 x (16 + 26)/2 = 6.3 iku
3.a. 2(u)
3.b. 2(u) 6(disz)
3.c. 2(iku) 1/2(iku) bar
calculation: (20 × 26)/2 = 2.6 iku
4.a. 3(u)
4.b. 4(u) 5(disz)
4.c. 1(esze3) 1/2(iku) 1/4(iku) bar
calculation: (30 × 45)/2 = 6.75 iku
5.a. 4(u) 5(disz)
5.b. 5(u) 5(disz)
5.c. 1(bur3) 1(esze3) 1/2(iku) 1/4(iku) bar
calculation: 45 × 55 = 24.75 iku
6.a. 4(u)
6.b. 1(u) 3(disz)
6.c. 5(iku) 1/4(iku) ki
calculation: 40 × 13 = 5.2 iku
7.a. 4(u)
7.b. 2(u) 3(disz)
7.c. 4(iku) 1/2(iku) ki
calculation: (40 × 23)/2 = 4.6 iku
8. 1(u)
9.a. 3(u)
9.b. 1(iku) 1/2(iku) ki
calculation: (30 × 10)/2 = 1.5 iku
10.a. 1(u) 2(disz)?
10.b. 1(iku) 1/4(iku) ki
calculation: 12 × 10 = 1.2 iku
11. 1(u)
12. 1(gesz2)
13.a. 1(gesz2)
13.b. 1(u)
13.c. 1(esze3) ki
calculation: 60 × 10 = 6 iku
14. 1(gesz2)
15.a1. 1(u) 1(disz)
15.a2. 1(u) 1(disz)
15.b. 1(gesz2)
calculation: 11 × 60 = 6.6 iku (?)
16.a. 1(u) 5(disz)
16.b1. 2(u)
16.b2. <3(u)>
16.c. 3(iku) 1/2(iku) 1/4(iku) bar
calculation: 15 x (20 + 30)/2 = 3.75 iku (?)
17.a1. 1(u) 5(disz)
17.a2. 2(u)
17.b. 4(u) 5(disz)
17.c. 1(esze3) 1(iku) 1/2(iku) 1/4(iku) bar
calculation: (15 + 20)/2 × 45 = 7.875 iku (?)
18.a. 4(u) 5(disz)
18.b. 1(gesz2) 5(disz)
18.c. 1(gesz2) 5(disz)
18.d. 1(bur3) 1(esze3) 5(iku) 1/4(iku) bar
calculation: 45 × 65 = 29.25 iku
19. 3(u) 5(disz)
20.a. 3(u)
20.b. 2(u)
20.c. 3(iku) ki
calculation: (20 × 30)/2 = 3 iku
21.a. 4(u)
21.b. 2(u)
21.c. 1(esze3) 2(iku)
calculation: 40 × 20 = 8 iku
22.a. 3(u)
22.b. 1(u) 5(disz)!
22.c. 2(iku) 1/4(iku) ki
calculation: (30 × 15)/2 = 2.25 iku
23. 2(gesz2) 4(u)
calculation: 10 + 30 + 20 + 30 + 55 + 15 = 160
24. 2(gesz2) 1(u)
calculation: 40 + 40 + 10 + 30 + 10 + 10 + 20 = 180 ?

reverse
1. 1(bur3) 1(esze3) GAN2 a-sza3 tur
2. 4(bur3) 1(esze3) 2(iku) 1/4(iku) GAN2 bar
3. 1(bur'u) 1(bur3) 3(iku) GAN2 sza3 temen
4. szunigin 1(bur'u) 7(bur3) la2 1/2(iku) 1/4(iku) GAN2
5. a-sza3 u2-du-lu2-saga!?
hand copy has lu2-{d}szara2
blank space



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