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| Anonymous 482083 Click for archival page
Can you improve upon the content of this entry? Please contact us! | ![]() (click on image to enlarge) | Tablet obverse column 1 beginning broken 1.a'. [...] 1(N14)# , [...] SZE~a 1.b'. [N] , TAR~a 2.a'. 3(N01) , SZE~a KASZ~b? |U4x3(N01)| 2.b'. 1(N42~a) 1(N25) , TAR~a calculation: 3(N01) รท 10 = 1(N39) 1(N24) column 2 beginning broken 1'. [N] 1(N14) , [...] 2'. 3(N01) , X [...] 3'. , X [...] reverse (not given) Version History |